(3y^2+2)(y+3)=y+14

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Solution for (3y^2+2)(y+3)=y+14 equation:


Simplifying
(3y2 + 2)(y + 3) = y + 14

Reorder the terms:
(2 + 3y2)(y + 3) = y + 14

Reorder the terms:
(2 + 3y2)(3 + y) = y + 14

Multiply (2 + 3y2) * (3 + y)
(2(3 + y) + 3y2 * (3 + y)) = y + 14
((3 * 2 + y * 2) + 3y2 * (3 + y)) = y + 14
((6 + 2y) + 3y2 * (3 + y)) = y + 14
(6 + 2y + (3 * 3y2 + y * 3y2)) = y + 14
(6 + 2y + (9y2 + 3y3)) = y + 14
(6 + 2y + 9y2 + 3y3) = y + 14

Reorder the terms:
6 + 2y + 9y2 + 3y3 = 14 + y

Solving
6 + 2y + 9y2 + 3y3 = 14 + y

Solving for variable 'y'.

Reorder the terms:
6 + -14 + 2y + -1y + 9y2 + 3y3 = 14 + y + -14 + -1y

Combine like terms: 6 + -14 = -8
-8 + 2y + -1y + 9y2 + 3y3 = 14 + y + -14 + -1y

Combine like terms: 2y + -1y = 1y
-8 + 1y + 9y2 + 3y3 = 14 + y + -14 + -1y

Reorder the terms:
-8 + 1y + 9y2 + 3y3 = 14 + -14 + y + -1y

Combine like terms: 14 + -14 = 0
-8 + 1y + 9y2 + 3y3 = 0 + y + -1y
-8 + 1y + 9y2 + 3y3 = y + -1y

Combine like terms: y + -1y = 0
-8 + 1y + 9y2 + 3y3 = 0

The solution to this equation could not be determined.

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